Abstract
[Objective]To study the influence of different fertilizer ratio on sweet potato yield,and provide reference for balanced fertilization of sweet potato.[Method] With Xushu 22 as material,non-fertilizer as control,effects of different fertilizer ratio on the growth of aboveground parts,underground parts and the yield were studied.[Result]The results showed that phosphorus(P) and potassium(K) are key fertilizers for the yield of Xushu 22.And in all processing with P and K,such as N + P + K,P + K and the compound fertilizer,the fresh base yield of Xushu 22 was raised at a certain level.With the treatment of P + K,Xushu 22 had the highest fresh base yield.And the yield increased at a significant level,which was 16.03%.The N + P + K treatment followed by 7.04%,while with the N + P treatment,the aboveground parts had excessive growth.[Conclusion]Under the medium fertility soil conditions,in order to have high sweet potato yield,we should pay attention to the mix of P and K,and fertilize no or less nitrogen.
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Claims 6
Claim · model-written summary
Phosphorus and potassium were identified as key fertilizers for Xushu 22 yield.
- Taxon
- Sweet potato
Ipomoea batatast0 - Material
- Xushu 22e0
- Outcome
- yielde0
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
_Flower.jpg?width=500)
Verbatim
t0“Sweet potato”
e0“phosphorus(P) and potassium(K) are key fertilizers for the yield of Xushu 22”
Claim · model-written summary
N + P + K raised fresh base yield.
- Taxon
- Sweet potato
Ipomoea batatast0 - Material
- Xushu 22e0
- Treatment
- N + P + Ke0
- Outcome
- fresh base yielde0
- Direction
- raisede0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
_Flower.jpg?width=500)
Verbatim
t0“Sweet potato”
e0“in all processing with P and K,such as N + P + K,P + K and the compound fertilizer,the fresh base yield of Xushu 22 was raised at a certain level”
Claim · model-written summary
P + K produced the highest fresh base yield, a significant 16.03% increase.
- Taxon
- Sweet potato
Ipomoea batatast0 - Material
- Xushu 22e0
- Treatment
- P + Ke0
- Outcome
- fresh base yielde0
- Direction
- higheste0
- Value
- 16.03%e0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
_Flower.jpg?width=500)
Verbatim
t0“Sweet potato”
e0“With the treatment of P + K,Xushu 22 had the highest fresh base yield.And the yield increased at a significant level,which was 16.03%”
Claim · model-written summary
The N + P + K treatment increased yield by 7.04%.
- Taxon
- Sweet potato
Ipomoea batatast0 - Treatment
- N + P + Ke0
- Outcome
- yielde1
- Direction
- increaseinferrede0
- Value
- 7.04%e0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
_Flower.jpg?width=500)
Verbatim
t0“Sweet potato”
e0“The N + P + K treatment followed by 7.04%”
e1“the fresh base yield of Xushu 22 was raised at a certain level”
Claim · model-written summary
N + P caused excessive aboveground growth.
- Taxon
- Sweet potato
Ipomoea batatast0 - Treatment
- N + P treatmente0
- Outcome
- aboveground parts had excessive growthe0
- Direction
- excessive growthe0
Not reportedComparator
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
_Flower.jpg?width=500)
Verbatim
t0“Sweet potato”
e0“with the N + P treatment,the aboveground parts had excessive growth”
Claim · model-written summary
Under medium fertility, authors recommended P and K with no or less nitrogen for high yield.
- Taxon
- Sweet potato
Ipomoea batatast0 - Outcome
- pay attention to the mix of P and K,and fertilize no or less nitrogene0
- Qualifier
- medium fertility soil conditionse0
Organisms pictured · Representative pictures of the matched species, not figures from the paper.
_Flower.jpg?width=500)
Verbatim
t0“Sweet potato”
e0“Under the medium fertility soil conditions,in order to have high sweet potato yield,we should pay attention to the mix of P and K,and fertilize no or less nitrogen”
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